Voltage Divider Simulation

Overview

This example demonstrates a basic voltage divider circuit using PyAMS, which is commonly used to scale down voltages. The circuit consists of:

  • A DC voltage source V1

  • Two resistors R1 and R2 in series

  • The output voltage is measured across R2

The circuit divides the voltage proportionally based on the resistor values.

Circuit Diagram

Voltage Divider Circuit

Explanation

According to the voltage divider rule, the voltage across R2 is given by:

\[V_{out} = V_{in} \cdot \frac{R2}{R1 + R2}\]

Given: - \(V_{in} = 15V\) - \(R1 = R2 = 2k\Omega\)

Then:

\[V_{out} = 15 \cdot \frac{2000}{2000 + 2000} = 7.5V\]

The current through the series resistors is:

\[I = \frac{V_{in}}{R1 + R2} = \frac{15}{4000} = 3.75mA\]

Python Simulation Code

from pyams.lib import model, signal, param
from pyams.lib import voltage, current

# Resistor model using Ohm's Law
class resistor(model):
    def __init__(self, p, n):
        self.V = signal('in', voltage, p, n)
        self.I = signal('out', current, p, n)
        self.R = param(1000.0, 'Ω', 'Resistance')
        self.Pout = param(1000.0, 'Ω', 'Resistance')

    def analog(self):
        self.I += self.V / self.R

from pyams.lib import circuit
from pyams.models import DCVoltage

# Define elements
V1 = DCVoltage('n1', '0')
R1 = resistor('n1', 'n2')
R2 = resistor('n2', '0')

# Set component parameters
V1.setParams("Vdc=15V")
R1.setParams("R=2kΩ")
R2.setParams("R=2kΩ")

# Create and simulate circuit
myCircuit = circuit()
myCircuit.addElements({'V1': V1, 'R1': R1, 'R2': R2})
myCircuit.analysis(mode='op')
myCircuit.run()

# Output results
myCircuit.print('n2', R1.I)

Simulation Results

Output Voltage at node n2: 7.5 V
Output Current through R1: 3.75 mA